Question

Para una fibra óptica con índice n1=1,5 y una cubierta de índice n2=1,4 ¿cuál es su apertura numérica?

For an optical fiber with index n1 = 1.5 and a cover with index n2 = 1.4, what is its numerical aperture?

Answer 1

Answer:

$0.54$

Explanation:

$NA=\sqrt{n_1^2-n_2^2}$

Substitute known values

$NA=\sqrt{1.5^2-1.4^2}=\sqrt{0.29} = 0.54$