Answer:
Explanation:
The question is not completely clear because some missing parts or grammar (syntax) errors.
Interpreting it, the question is what is the Kelvin temperatue of the air in a tire, when the pressure in the tire has increased to 225 kPa, if the initial conditions of the air inside the tire were 188kPa of pressure and a temperature of 32ºC.
To solve this, you can assume constant volume and use the law of Gay-Lussac for ideal gases:
[tex]\dfrac{P_1}{T_{1}}=\dfrac{P_2}{T_2}[/tex]
That equation works with absolute temperatures, i.e. Kelvin.
Then solve for T₂, substitute and compute:
[tex]T_2=P_2\times \dfrac{T_1}{P_{1}}=225kPa\times \dfrac{305.15K}{188kPa}[/tex]
[tex]T_2=413.90K\approx 414K\longleftarrow answer[/tex]