Respuesta :
Answer with explanation:
The equation for nth root of unity is
[tex]Z^n=1\\\\Z=(1)^{\frac{1}{n}}\\\\Z=[cos (2k\pi+ 0)+i sin(2k\pi+ 0)]^{\frac{1}{n}}\\\\Z=cos(\frac{2k\pi}{n})+i sin(\frac{2k\pi}{n})=e^{\frac{2k\pi}{n}}[/tex]
Where,k=0,1,2,3......(n-1).
there will be n-roots of the above equation.
For,different values of k,there will be different Z.
[tex]Z=1,e^{\frac{2\pi}{n}} ,e^{\frac{4\pi}{n}},e^{\frac{6\pi}{n}},e^{\frac{8\pi}{n}},....e^{\frac{2(n-1)\pi}{n}[/tex]
Used,Euler's Identity
[tex]e^{i\alpha}=cos\alpha + isin\alpha[/tex]
For different values of k , the different roots of unity will be
Z = [tex]\rm 1 , e^{2\pi / n} , \rm e^{4\pi / n}[/tex]....................
What is Euler's Identity ?
According to Euler Identity , [tex]\rm e^{i\pi}[/tex] = -1
It is asked to determine nth root of Unity or any value of n
Zⁿ = 1
Z = [tex]\rm 1^{1/n}[/tex]
By Euler's Formula
Z = { cos ( 2kπ +0 ) + isin ( 2kπ +0 )}
Z = cos ( 2kπ / n) + isin ( 2kπ / n)
From euler' identity this can be written as
Z = [tex]\rm e^{2k\pi / n}[/tex]
where k = 0 , 1 , 2 , 3..... (n-1)
So , the roots of unity will be n different roots.
Therefore , For different values of k , the different roots are as follows
Z = [tex]\rm 1 , e^{2\pi / n} , \rm e^{4\pi / n}[/tex]....................
To know more about Euler's Identity
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