Respuesta :
Question;
Assumption:
Let us assume Brandon's running speed is = 18.30 and
Ruben's running speed is = 16.50 and
Answer:
The two equations that can represent the relationship between the meters and second for Brandon and Ruben are;
Brandon → Y₁ = 18.3·X₁ and
Ruben → Y₂ = 16.5·X₂
Step-by-step explanation:
The equation is of the form
Y = 17.45·X
That is Amy ran Y meters in X seconds
Therefore we have
[tex]17.45 = \frac{Y}{X}[/tex] or the value 17.45 is the running speed of Amy
Therefore, where the running speed of Brandon is 18.30 and the running speed of Ruben is 16.50 we have
Y meters ran by Brandon in X seconds given by
Y₁ = 18.3·X₁ and
For Ruben we have Y meters ran in X seconds given by
Y₂ = 16.5·X₂.
Answer:
Brandon : Y = BX, where B is the speed (positive integer) and X is the time in seconds.
Ruben : Y = RX, where R is the speed (positive integer) and X is the time in seconds.
Step-by-step explanation:
For Amy, the relationship between the distance run and the time taken is represented by the equation Y equals 17.45X, where she ran Y meters in X seconds.
Therefore we have,
Y = 17.45X
Y/X = 17.45 m/s, where m/s is meter per second.
Let us assume that the speed for Brandon is represented by B and that of Ruben is represented by R.
For Brandon, we obtain Y/X = B m/s
Y = BX
For Ruben, we obtain Y/X = R m/s
Y = RX
High School Mathematics 5+3 pts
The relationship between the distance run and the time for Amy can be represented by the equation Y equals 17.45X, where she ran Y meters in X seconds.