Respuesta :

Atomic mass of Helium is 4u = 2protons + 2 Neutrons = 1 atom 
No. of atoms in 52u = 52/4 = 13 atoms

52g of heliume
6.022*10^23*52/4 atoms of he
7.829*10^24 atoms of he

1mole of he =6.023*1023
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