Question

a ball is thrown from an initial height of 5 feet with an initial upward velocity of 37 ft/s. the balls height h (in feet) is t seconds is given by the following. h=5+37t-16t^2 find all values of t for which the balls height is 25 feet. round your answer(s) to the nearest hundredth

Answer 1

Basically you use quadratic formula and t is equal to 0.86 or 1.45

Answer 2

Given :

The ball's height is given by

$h=5+37t-16t^2$

Step-by-step explanation:

We need to find the value of t when height is 25 feet.

Lets substitute height h by 25  and solve for 't'

$h=5+37t-16t^2\\\\25=5+37t-16t^2\\\\Add \; 16t^2 \; and \; subtract\; 37t \\16t^2-37t+20=0$

Apply quadratic formula to solve for t

$x=\frac{-b+-\sqrt{b^2-4ac} }{2a} \\t=\frac{37\pm \sqrt{37^2-4\left(16\right)\left(20\right)}}{2\left(16\right)}\\\\t=\frac{37\pm \sqrt{89}}{2\left(16\right)}\\\\t=\frac{37-\sqrt{89}}{32},\:t=\frac{37+\sqrt{89}}{32}\\t=0.86,\:t=1.45$

Final Answer

The values of t  are t=0.86 or  t=1.45

Reference : https://brainly.com/question/15810288