Question

The hypotenuse of a right triangle is three times the length of one of its legs. The length of the other leg is four feet. Find the
lengths of the three sides of the triangle. For non-integer answer(s), round your answer(s) to the nearest tenth.
Provide your answer below:

Answer 1

Answer: Your sides should be 0.7, 2, and 2.1

Step-by-step explanation:

Let x be one of the legs of the right triangle.

$x^2+\sqrt{4}^2=(3x)^2$

Simplify the expression.

$x^2 +4 = 9x^2$

Move the similar terms to the other side.

$4=9x^2-x^2$

$4 = 8x^2$

Simplify this expression to solve for x.

$x^2=\frac{4}{8}$

$x^2 = \frac{1}{2}$

$x=\sqrt\frac{1}{2} = \frac{\sqrt{2}}{2} = 0.707$ is one side

$0.707 * 3 = 2.121$ is the hypotenuse

Check:

$0.707^2 + 4 = 2.121^2$ (Correct)