Question

At a temperature of -33.0 degrees C, a sample of confined gas exerts a pressure of 53.3 kPa. If volume remains constant, at what temperature will the pressure reach 133 kPa?

Answer 1

Answer: 598.9K = 325.9°C

Explanation:

P1= 53.3kPa T1= -33+273=240K

P2=133kPa , T2= ?

Applying P1/T1 = P2/T2

Substitute and Simplify

53.3/240 = 133/T2

T2= 598.9K = 325.9°C