Respuesta :

Answer:

[tex]cos(G)=\frac{28}{53}[/tex]

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In the right triangle EFG

[tex]cos(G)=\frac{GF}{EG}[/tex] ----> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

[tex]cos(G)=\frac{28}{53}[/tex]

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