Question

Factor the polynomial 12c9 + 28c7. Find the GCF of 12c9 and 28c7. 4c7 Write each term as a product, where one factor is the GCF. 4c7(3c2) + 4c7(7) Use the distributive property.

Answer 1

We have been given a polynomial $12c^9+28c^7$. We are asked to factor the given polynomial.

First of all, we will find the greatest common factor of both terms.

GCF of $12$ and $28$ is 4 as 3 times 4 is 12 and 7 times 4 is 28.

GCF of $c^9\text{ and }c^7$ is $c^7$.

So GCF of $12c^9\text{ and }28c^7$ is $4c^7$.

Now we will rewrite each term as product of GCF and a term as:

$12c^9=4c^7(3c^2)$

$28c^7=4c^7(7)$

$4c^7(3c^2)+4c^7(7)$

Now we will factor out  $4c^7$ from both terms as:

$4c^7(3c^2+7)$

Therefore, factored form of our given expression would be $4c^7(3c^2+7)$.

Answer 2

Answer:

$4c7 (3c^{2} + 7)$

Step-by-step explanation:

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