At a local zoo, the number of resident birds is twice the number of four-legged mammals. If the total number of legs between the birds and mammals equals 80, how many birds are there?

Respuesta :

Mibo

Step-by-step explanation:

Total number of legs = 80

So if there are 10 mammals so there legs = 40

And the no of resident birds should be twice

So there are 20 resident birds and number of legs = 20 × 2 = 40

There are 20 birds.

What is Algebra?

Algebra is the part of mathematics that helps represent problems or situations in the form of mathematical expressions.

Given:

Total legs = 80

let the mammals be x

and, number of birds be 2x

Now, number of legs of birds = 2* 2x= 4x

and number of legs of mammals be= 4* x = 4x

Total legs = 80

4x+ 4x =80

8x= 80

x=10

So, the number of birds be = 2x= 20

Learn more about algebra here:

https://brainly.com/question/953809

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