contestada


What average force is required to stop a 1400 kg car in 8.0 s if the car is traveling at 95 km/h?

Respuesta :

Answer: -424.24 N

It's negative because the vehicle is in motion and we want to bring it to a full stop, therefore we must apply a force in the opposite direction.

Explanation:

[tex]F = ma\\\\F = Force\\m = mass (kg)\\a = acceleration (m/s^2)[/tex]

Find the acceleration

[tex]V_1 = 95km/h\\V_2 = 0[/tex]

Convert from km/h to m/s

[tex]95\frac{km}{h} (\frac{1000m}{1km} )(\frac{1h}{3600s} )= 26.39m/s[/tex]

[tex]a = \frac{V_2-V_1}{t}\\\\a = \frac{0-26.39m/s }{8s}\\\\a = -3.30m/s^2[/tex]

Plug this information into the original Force Formula

[tex]F =ma\\\\F = (1400kg)(-3.30m/s^2)\\F =-424.24 N[/tex]