Question

A 5.45 L sample at 10.0°C and a pressure of 64.7 kPa is allowed to expand to a volume of 18.50L. The final pressure of the gas is 58.0 kPa. What is the final temperature of the gas in degrees Celsius?

Answer 1

Answer: $481^0C$

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 64.7 kPa

$P_2$ = final pressure of gas = 50.8 kPa

$V_1$ = initial volume of gas = 5.45 L

$V_2$ = final volume of gas = 18.50 L

$T_1$ = initial temperature of gas = $10^oC=273+10=283K$

$T_2$ = final temperature of gas = ?

Now put all the given values in the above equation, we get:

$\frac{64.7kPa\times 5.45}{283K}=\frac{50.8kPa\times 18.50}{T_2}$

$T_2=754K=(754-273)^0C=481^0C$

Thus final temperature of the gas in degrees Celsius is 481