Question

Baseball is hit vertically over home plate. The ball's height h (in feet) above the ground is modeled by , where t is measured in seconds. 2ht t t ( ) 16 48 4 =− + + 1. What is the initial height of the baseball?

Answer 1

Answer:

The initial height of the base ball based on the equation for the height of the base ball, $h = -16t^2 + 32t + 3$ is 3 ft

Step-by-step explanation:

For clarity, if we put the equation of the height of the base ball as

$h = -16t^2 + 32t + 3$

Then the initial height of the base ball will be at the point t = 0

That is

$h = -16(0)^2 + 32(0) + 3$ or

h = 3 ft

The initial height of the base ball based on the equation for the height of the base ball, $h = -16t^2 + 32t + 3$ is then = 3 ft.