Question

what is the 8th term in the sequence? 14, 18, 116, 132, ...

Answer 1

$a_1=14;\ a_2=18\\\\d=a_2-a_1\to d=18-14=4\\\\a_n=a_1+(n-1)d\\\\a_n=14+(n-1)\cdot4=14+4n-4=10+4n\\\\a_8=10+4\cdot4=10+16=36\\\\Answer:\boxed{a_8=36}$