Question

find the value of sin(θ) for an angle θ in standard position with a terminal ray that passes through the point (-5, -12)
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Answer 1

Answer:

c. -12/13

Step-by-step explanation:

it will be the y-coordinate divided by the distance from the origin, or (-12) / $\sqrt{5^2+12^2}$ = -12/13

Answer 2

Answer:

C. -12/13

Step-by-step explanation:

(-5,-12) is in the third quadrant

So sin would be negative

Hypotenuse = sqrt(5² + 12²)

sqrt(169)

13

sin(theta) = -12/13