Question

Evaluate Loga√44+ Log a√275- Log 11a
They all have base 10

Answer 1

Answer:

$log(10a)$

Step-by-step explanation:

$log(a\sqrt{44})+log(a \sqrt275)-log(11a)$

We can simplify this using these log laws:

$log(a)+log(b)=log(ab)\\log(a)-log(b)=log(\frac{a}{b})$

$log(\frac{a^2\sqrt{44} \sqrt{275}}{11a})$

We also have laws to simplify square roots

$\sqrt{a}*\sqrt{b} = \sqrt{ab}$

So this becomes

$log(\frac{a^2\sqrt{12100}}{11a})$

$\sqrt{12100} = 110$

so this becomes

$log(\frac{110a^2}{11a})=log(10a)$