Respuesta :

Answer:

0.7 mol of CaCl2 is produced.

Explanation:

First, you have to create a balanced equation :

Ca(OH)2 + 2HCl -> CaCl2 + 2H2O

Next, we have to find the ratio using the coefficients of the equation :

1Ca(OH)2 + 2HCl -> 1CaCl2 + 2H20

Ratio,

1 : 2 : 1 : 2

By looking at the ratio, we know that 2 ratio of HCl react to produce 1 ratio of CaCl2. Now, we can find the mole of CaCl2 :

ratio of 2 = 1.4 mol

ratio of 1 = 0.7 mol

The moles of calcium chloride produced from 1.4 moles HCl has been 0.7 moles.

The balanced chemical equation for the reaction has been:

[tex]\rm Ca(OH)_2\;+\;2HCl\rightarrow\;CaCl_2\;+\;H_2O[/tex]

Computation for Moles of Calcium Chloride produced

From the balanced chemical equation, there has been production of 1 mole of calcium chloride, from 2 moles of HCl. The moles of calcium chloride formed from 1.4 moles HCl has been:

[tex]\rm 2\;mol\;HCl=1\;mol\;CaCl_2\\1.4\;mol\;HCl=\dfrac{1}{2}\;\times\;1.4\;mol\;CaCl_2\\1.4\;mol\;HCl=0.7\;mol\;CaCl_2[/tex]

The moles of calcium chloride produced from 1.4 moles HCl has been 0.7 moles.

For more information about moles produced, refer to the link:

https://brainly.com/question/10606802