Respuesta :
Answer:
0.7 mol of CaCl2 is produced.
Explanation:
First, you have to create a balanced equation :
Ca(OH)2 + 2HCl -> CaCl2 + 2H2O
Next, we have to find the ratio using the coefficients of the equation :
1Ca(OH)2 + 2HCl -> 1CaCl2 + 2H20
Ratio,
1 : 2 : 1 : 2
By looking at the ratio, we know that 2 ratio of HCl react to produce 1 ratio of CaCl2. Now, we can find the mole of CaCl2 :
ratio of 2 = 1.4 mol
ratio of 1 = 0.7 mol
The moles of calcium chloride produced from 1.4 moles HCl has been 0.7 moles.
The balanced chemical equation for the reaction has been:
[tex]\rm Ca(OH)_2\;+\;2HCl\rightarrow\;CaCl_2\;+\;H_2O[/tex]
Computation for Moles of Calcium Chloride produced
From the balanced chemical equation, there has been production of 1 mole of calcium chloride, from 2 moles of HCl. The moles of calcium chloride formed from 1.4 moles HCl has been:
[tex]\rm 2\;mol\;HCl=1\;mol\;CaCl_2\\1.4\;mol\;HCl=\dfrac{1}{2}\;\times\;1.4\;mol\;CaCl_2\\1.4\;mol\;HCl=0.7\;mol\;CaCl_2[/tex]
The moles of calcium chloride produced from 1.4 moles HCl has been 0.7 moles.
For more information about moles produced, refer to the link:
https://brainly.com/question/10606802