Respuesta :

Answer:

x^2-9x+14

Step-by-step explanation:

(x-2)(x-7) = x^2-9x+14

A quadratic function whose zeros are 2 and 7 is [tex]f(x) = x^2 - 9x+14[/tex]

If the zeros of a quadratic function are a and b, the quadratic function will be given as:

f(x)  =  (x  -  a)(x  -  b)

For the function f(x) whose zeros are 2 and 7:

f(x)  =  (x  -  2)(x  -  7)

Expand the equation

[tex]f(x)=x^2-7x-2x+14\\\\f(x) = x^2 - 9x+14[/tex]

Therefore, a quadratic function whose zeros are 2 and 7 is [tex]f(x) = x^2 - 9x+14[/tex]

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