Respuesta :

Answer:

A.) ∆KHM ≅ ∆KJM

Step-by-step explanation:

In triangle KHJ, KM is the bisector of base HJ..(given)

[tex] \therefore \: HM \cong \: JM...(1) \\ In\: \triangle KHM \:\& \: \triangle KJM\\

KH\cong KJ... (given) \\

KM \cong KM.. (common\: side) \\

HM \cong JM... [From\: equation \: (1)]\\

\therefore \triangle KHM \cong\triangle KJM\\.. (By\:SSS\: Postulate) \\ [/tex]

Answer:

KHM = KJM or A.)

Step-by-step explanation:

YURTTTTT