Question

PLEASE HURRY DOUBLE POINTS+BRAINLY my question is in the picture​

Answer 1

Answer:

(6, - 5)

Step-by-step explanation:

The equation of circle in centre radius form is:

$(x - h)^{2} + (y - k)^{2} = {r}^{2} \\ plugging \: h = 3 \: \: k = - 9 \: and \: r = 5 \\ (x - 3)^{2} + \{y - ( - 9) \}^{2} = {5}^{2} \\ (x - 3)^{2} + (y + 9)^{2} = 25 \\ let \: us \: plug \: x = 6 \: and \: y = - 5 \: in \: lhs \\ lhs = (6 - 3) ^{2} + ( - 5 + 9) ^{2} \\ = (3) ^{2} + ( 4) ^{2} \\ = 9 + 16 \\ = 25 \\ = rhs \\ hence \: (6, \: \: - 5) \: is \: on \: the \: circle.$

Answer 2

Answer:

Answer is option b) (6,-5)

Step-by-step explanation:

$given \: that \: \\ centr e\: of \: circle \: is(3, - 9) \\ and \: radius \: is \: 5 \\ when \: \: we \: calculate \: the \: distance \: between \: (3, - 9) \: and \: (6, - 5) \\ distance \: = \sqrt{ {(x1 - x2)}^{2} + {(y1 - y2)}^{2} } \\ here \: x1 = 3 \: \: y1 = - 9 \\ x2 = 6 \: \: \: \: y2 = - 5 \\ on \: substituting \: the \: values \\ = \sqrt{(3 - 6) + {( - 9 + 5)}^{2} }^{2 } \\ = \sqrt{ { - 3}^{2} + { - 4}^{2} } \\ = \\ = \sqrt{9 + 16} \\ = \sqrt{25} \\ = 5$

(6 -5) is a point on the circle.

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