Answer:
(9, -7)
Step-by-step explanation:
[tex]x^2+y^2+18x+14y+105=0\\[/tex]
Rearrange like x and y terms next to each other, then complete the square on both.
[tex](x-9)^2-361 + (y+7)^2 - 49 + 105 = 0[/tex]
The negative of the # numbers instead the brackets give you the centre of the circle.
