Respuesta :

Answer:

like this watch.

Step-by-step explanation:

Using the first equation, solve for x:

[tex]3x+8y=15\\[/tex]

Subtract 8y from both sides

[tex]3x+8y-8y=15-8y\\3x=15-8y[/tex]

Divide both sides by 3

[tex]\frac{3x}{3}=\frac{15-8y}{3} \\\\x=5-\frac{8y}{3}[/tex]

Keep that in mind...Now solve for y

[tex]3x+8y=15[/tex]

Subtract 3x from both sides

[tex]3x-3x+8y=15-3x\\8y=15-3x[/tex]

Divide both sides by 8

[tex]\frac{8y}{8}=\frac{15-3x}{8} \\\\y=\frac{15-3x}{8}[/tex]

Now, plug these into 2x+8y

[tex]2(5-\frac{8y}{3})+8(\frac{15-2x}{8})[/tex]

Simplify

[tex]10-\frac{16y}{3} +15-2x\\\\-2x-\frac{16y}{3} +25[/tex]

omg nevermind

it goes on forever

You don't solve this

Unless....

You messed up on 2x+8y and forgot the equal sign, which would make it an equation...I got played.

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