Question

9. Point N (2, 1) is on segment RS. A translation moves point N to its image,
N' (-6, 16). What is the distance, in units, between any point on segment RS
and its image?

Answer 1

Answer:

17

Step-by-step explanation:

Use the distance formula

$d=\sqrt{(x2-x1)^2+(y2-y1)^2}\\\\ d=\sqrt{(-6-2)^2+(16-1)^2}$

Simplify the parentheses  

$d=\sqrt{(-8)^2+(15)^2}$

Simplify exponents

$d=\sqrt{64+225}$

Add

$d=\sqrt{289}$

Simplify

$d=17$

Done.