If the coefficient of friction for a drag racer's tires on concrete is 1.2 and the drag racer weighs 10,000 N, how much friction force pushes the care forward?

Respuesta :

Answer:

12kN

Explanation:

Remembering that Force is proportional to Reaction force and coefficient of friction.

[tex]F = \mu R\\F = 1.2 * 10000\\F = 120000N[/tex]

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