Respuesta :
Answer:
The appropriate response is yes. Because of Total internal reflection.
At the point when edge of rate is sufficiently huge (more noteworthy than the basic angle),Snell's law can not have the option to settle for edge of refraction now,because it will show refracted edge has sin more prominent than 1,which is preposterous.
In this case,all lights are completely reflected off the interface,obeying law of reflection, this wonders is called Total Internal Reflection.
When the Angle of Incidence is large enough the beam will be completely reflected this is because of Total Internal Reflection.
Total Internal Reflection
The law of reflection states that the angle of the reflected ray is equal to the angle of the incident ray. But in the given question we are given that the angle of incidence is larger than the reflected ray.
This is due to Total Internal Reflection, because when the angle is increased to greater angles, we will find that there is less refraction and more reflection, this when the angle of incidence is increased.
Hence, the given scenario is because of Total Internal Reflection.
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