Slope-intercept form: y = mx + b
(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)
For lines to be parallel, they need to have the same slope.
[tex]y=-\frac{2}{3} x+12[/tex] The slope is -2/3, so the parallel line's slope is also -2/3.
Now that you know the slope, substitute/plug it into the equation.
y = mx + b
[tex]y=-\frac{2}{3} x+b[/tex] To find b, plug in the point (6, -11) into the equation, then isolate/get the variable "b" by itself
[tex]-11=-\frac{2}{3}(6)+b[/tex]
-11 = -4 + b Add 4 on both sides to get "b" by itself
-7 = b
[tex]y=-\frac{2}{3} x-7[/tex]