which equation is the slope-intercept form of the line that passes through (6, -11) and is parallel of y = -2/3x + 12?

Respuesta :

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be parallel, they need to have the same slope.

[tex]y=-\frac{2}{3} x+12[/tex]    The slope is -2/3, so the parallel line's slope is also -2/3.

Now that you know the slope, substitute/plug it into the equation.

y = mx + b

[tex]y=-\frac{2}{3} x+b[/tex]   To find b, plug in the point (6, -11) into the equation, then isolate/get the variable "b" by itself

[tex]-11=-\frac{2}{3}(6)+b[/tex]

-11 = -4 + b     Add 4 on both sides to get "b" by itself

-7 = b

[tex]y=-\frac{2}{3} x-7[/tex]    

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