Answer:
Yes.
Step-by-step explanation:
You can find it out by factoring but ill do it easier way.
(x + 1 ) = 0 put the first and second equation to 0
x = -1
x³ + 2x² - 5x - 6 = 0 Now plug in the x in the equation
(-1)³ + 2(-1)² - 5(-1) - 6 = 0
0 = 0
so (x + 1) is a factor.
Answer:
Yes
Step-by-step explanation:
If x + 1 is a factor
x = -1 should be a root
Check for the remainder:
(-1)³ + 2(-1)² −5(-1) − 6
0
Therefore it's a root, hence x+1 is a factor