Respuesta :

Answer:

[tex]m\angle ABC=46^o[/tex]

Step-by-step explanation:

step 1

we know that

The inscribed angle is half that of the arc it comprises.

so

[tex]m\angle ADC=\frac{1}{2}(arc\ AC)[/tex]

we have

[tex]m\angle ADC=23^o[/tex]

so

[tex]23^o=\frac{1}{2}(arc\ AC)\\arc\ AC=46^o[/tex]

step 2

we know that

Central angle is the angle that has its vertex in the center of the circumference and the sides are radii of it

so

[tex]m\angle ABC=arc\ AC[/tex] ----> by central angle

therefore

[tex]m\angle ABC=46^o[/tex]

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