The molarity of a solution of HNO₃ that contains 12.6 grams HNO₃ in 1L of solution is 0.2M.
Molarity of any solution is define as the number of moles of solute present in per liter of the soultion, i.e.
M = n/V
Moles of any substance will be calculated as:
n = W/M, where
W = given mass
M = molar mass
Moles of HNO₃ will be:
n = 12.6g / 63g/mol = 0.2 moles
Given volume of solution = 1 L
Molarity of solution = 0.2mol / 1L = 0.2M
Hence resultant molarity is 0.2M.
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