Answer:
Example to help you out!
May rides her bike the same distance that leah walks. may rides her bike 10 km/h faster than leah walks. if it takes may 1 h and leah 3 h to travel that distance, how fast does each travel?
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May DATA:
time = 1 hr. ; rate = x+10 mph ; distance = rt = (x+10)*1 mi
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Leah DATA:
time = 3 hr. ; rate = x mph ; distance = rt = 3x mi
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Equation:
distance = distance
x+10 = 3x
2x = 10
x = 5 mph (Leah's rate)
x+10 = 15 mph (May's rate)
Step-by-step explanation:
