Respuesta :
Answer:
yes
Step-by-step explanation:
plug -3/2 into f(x)= [tex]2x^3 + 3x^2 - 8x - 12[/tex]
f(-3/2) = 2(-3/2)³+3(-3/2)²-8(-3/2)-12 = 0
-3/2 is a zero of the function
Answer:
Yes
Step-by-step explanation:
If the reminder is 0, -3/2 is a root
2(-3/2)³ + 3(-3/2)² − 8(-3/2) − 12
= 0
Therefore -3/2 is a root