Answer:
[tex]\bigtriangleup A\approx 82.41\ cm^2[/tex]
Step-by-step explanation:
-Assume the cans are arranged in a two by three dimensions.
-Therefore the length of the box is equivalent to 3 diameters and the width is equivalent to two diameters:
[tex]D=2r=2\times 4=8\ cm\\\\Length=3D=3\times 8=24\\\\Width=2D=2\times 8=16[/tex][tex]cm[/tex]
#The area of the cardboard box is calculated as:
[tex]Area=lw\\\\=24\times 16\\\\=384\ cm^2[/tex]
#The total bottom areas of the 6 cans is:
[tex]A_6=6\pi r^2\\\\=6\pi \times 4^2\\\\=301.593\ cm^2[/tex]
#The area not covered is the difference between the area of the box and the total bottom areas of the 6 cans:
[tex]\bigtriangleup A=A_b-A_c\\\\=384-301.593\\\\=82.407\ cm^2\\\\\approx 82.41\ cm^2[/tex]
Hence, the area not covered is approximately [tex]82.41\ cm^2[/tex]
*Note that whichever order of arrangement the cans assume, the areas of the boxes will be the same.