Question

A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the hot room?
Use StartFraction V subscript 1 over T subscript 1 EndFraction equals StartFraction V subscript 2 over T subscript 2 EndFraction..

2.19 L
3.33 L
3.68 L
5.60 L

Answer 1

the answer is 3.68 L

Answer 2

Answer:

3.68 L

Explanation:

use charle's law formula

v1(t2) = v2(t1)

and convert celsius to kelvin k=C+273.15

3.5L(313.15K) = v2(298.15K)

solve for v2 by dividing 298.15k on both sides

v2=3.68