Question

A sample of argon has a volume of 1.2 L at STP. If the temperature is
increased to 22°C and the pressure is lowered to 0.80 atm, what will
the new volume be, in L?​

Answer 1

Answer:

the new volume would be 1.62 L

Explanation:

stp is 0 degrees C or 273.15 K and 1atm for the pressure

22 degrees C is 295.15 K

use the combined gas law formula and solve for v2

v2=p1(v1)(t2)/p2(t1)

v2=1atm(1.2L)(295.15)/0.8atm(273.15K)

v2=1.62