Question

2 Marianna is painting a ramp for the school play that is in the shape of a right
triangular prism. The ramp has the dimensions shown. She will not paint the back or
bottom surfaces of the ramp.
Each can of paint covers 1,000 square inches. What is the fewest number of full cans
of paint Marianna will need? Circle the minimum number of cans.
Cans of Paint
50 in,60 in,48 in, 14in.
There are 8 cans of paint

Answer 1

Answer:

4

Step-by-step explanation:

14, 48, and 50 are a Pythagorean triple, so I assume those are the sides of the triangular base.  So the length of the prism is 60 inches.

The surface area of the prism, not including the back or bottom, is the sum of the rectangular face and the two triangular bases:

A = Lc + 2 (½ ab)

A = Lc + ab

Plugging in values:

A = (60)(50) + (14)(48)

A = 3672

The surface area is 3672 in².  Each bucket of paint covers 1000 in².  So Marianna needs 4 buckets of paint.

Answer 2

The fewest number of full cans of paint that Marianna will need assuming Each can of paint covers 1,000 square inches is 4.

Surface area

First step

Rectangular face= (60)(50)

Rectangular=3000

Triangular faces=1/2(14)(48)

Triangular faces=336

Total area=3,000+2(336)

Tota area=3,000+672

Surface area= 3672

Second step

Number of can=3672/1000

Number of can=3.672

Number of can=4 (Approximately)

Inconclusion the fewest number of full cans of paint that Marianna will need assuming Each can of paint covers 1,000 square inches is 4.

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