A regular decegom has a perimeter of 150 in and an apothem of ≈ 23.1 in. What is the area of this polygon to the nearest tenth of a square foot?

Respuesta :

Given:

Given that the perimeter of a regular decagon is 150 inches.

The apothem of a regular decagon is 23.1 inches.

We need to determine the area of the polygon.

Area of the regular decagon:

The area of the regular decagon can be determined using the formula,

[tex]A=\frac{1}{2}ap[/tex]

where a is the apothem and p is the perimeter of the polygon.

Substituting the values, we get;

[tex]A=\frac{1}{2}(23.1 \times 150)[/tex]

Multiplying, we get;

[tex]A=\frac{1}{2}(3465)[/tex]

Dividing, we get;

[tex]A=1732.5 \ in^2[/tex]

Thus, the area of the regular decagon is 1732.5 square inches.

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