Question

What is the molality of a solution containing 10.0 g of Na2SO4 dissolved in 1000.0 g of water?

Answer 1

Explanation:

1 litre of water is equal to 1000.0 g of water

we need to find molality of a solution containing 10.0 g of dissolved in  Na₂S0₄1000.0 g of water

1.For that find the molar mass

Na:  2 x 22.99= 45.98

S:  32.07

O:  4 x 16= 64

Total molar mass is 142.05

We have to find the number of moles, y

To find the number of moles divide 10.0g by 142.05 g/mol.

So the number of moles is 0.0704 moles.

For the molarity, you need the number of moles divided by the volume. So, 0.0704 mol/1 L.

The molarity would end up being 0.0704 M

The molality of a solution containing 10.0 g of Na2SO4 dissolved in 1000.0 g of water is  0.0704 M

Answer 2

The molarity of the solution should be containing 10.0 g of Na2SO4 dissolved in 1000.0 g of water is  0.0704 M.

Calculation of the molarity of the solution:

Since

1 liter of water is equal to 1000.0 g of water

But before that the molar mass should be

Na:  2 x 22.99= 45.98

S:  32.07

O:  4 x 16= 64

So, Total molar mass is 142.05

Now the no of moles should be

=  10.0g by 142.05 g/mol.

= 0.0704 moles.

hence, the molarity of the solution is0.0704 M.

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