Respuesta :

Remainder theorem again...

[tex]p(x)=x^3+x^2-4x-4[/tex]

[tex]p(-1)=(-1)^3+(-1)^2-4(-1)-4=0[/tex]

So Yes, [tex]x+1[/tex] is a factor.

Answer:

Yes

Step-by-step explanation:

If x + 1 is a factor, x = -1 has to be a root

(-1)³ + (-1)² - 4(-1) - 4

0

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