Question

3 George has a rectangular deck that is 9 feet wide and 6 feet long. He builds a
new deck that is double the length and width of the old deck. What is the area
of the new deck?
Show your work.
Answer:
square feet

Answer 1

Answer:

$Area=216\ ft^2$

Step-by-step explanation:

-Given that the dimensions of the new deck are double the dimensions of the old deck:

$New \ Length=2(Old \ Length)=2\times 9=18\ ft\\\\New \ Width=2(Old \ Width)=2\times 6=12\ ft$

#The area of the new deck can now be calculated as:

$Area=Length\times Width\\\\=18\times 12\\\\=216\ ft^2$

Hence, the area of the new deck is $216\ ft^2$

Answer 2

Applying the area of a rectangle, it is found that the area of the new rectangular deck is of 216 square feet.

The area of a rectangle of width w and length l is given by the multiplication of these two measures, that is:

$A = lw$

In this problem, the dimensions are:

• Width of 18 feet, hence $w = 18$.

• Length of 12 feet, hence $l = 12$.

Then:

$A = lw = 12(18) = 216$

The area of the new rectangular deck is of 216 square feet.

To learn more about a rectangle's area, you can take a look at https://brainly.com/question/14099239