Question

Give the number of real solutions,
(-3) -1-1
There (select)
(select)
real solution(s).
is one
are two
are no

Answer 1

Answer:

No real solutions.

Step-by-step explanation:

Square both sides:

$x-3=(x-1)^2\\

x-3=x^2-2x+1\\

x^2-3x+4=0$

Evaluate the discriminant:

$\Delta =3^2-4 \times 1 \times 4$

$= 9-16=-7<0$

Since $\Delta $ is less than zero, there are no real solutions.