Answer:
9 quarts of paint
Step-by-step explanation:
-Since, the bottom area is not painted, the total area would be the sum of the two isosceles faces and the two remaining rectangles.
#Area of Isosceles faces:
[tex]A=0.5b\times \perp h, \ \perp h=11.5\ ft, \\\\2b=2\times\sqrt{(12.72^2-11.5^2)}=10.8712\\\\2A=2\times 0.5\times 10.8712\times 11.5\ ft\\\\=125.0188\ ft^2[/tex]
#Area of the two rectangles:
[tex]A_1=lw\\\\=9\times 12.72\\\\=114.48\ ft^2\\\\A_2=lw, \ \ w=b=10.8712\\\\=9\times 10.8712\\\\=97.8408\\\\\therefore A=A_1+A_2\\\\=114.48+97.4808\\\\=212.3208\ ft^2[/tex]
#The total area to be painted is the sum of all faces:
[tex]Total \ Area=125.0188+212.3208=\\\\=337.3396\ ft^2[/tex]
Since, the area would be covered twice and that 1 quart covers 80 sq ft. Let X be the number of quarts of paint:
[tex]Area \ Covered= 2Area\\\\=2\times 337.3396\\\\=674.6792\ ft^2\\\\80 \ ft^2=1qt\\674.6792\ ft^2=X\\\\X=\frac{674.6792}{80}\\\\=8.43349\approx 9\ qts\ of \ paint[/tex]
Hence, you need to buy approximately 9 quarts of paint.