The concentration of diluted solution is found to be 0.421 M
Explanation:
It is given that a stock solution (400 ml) should be diluted to 750 ml, we need to find the concentration of the diluted solution using the Law of Volumetric analysis,
V1M1 = V2M2
V1 being the volume of the stock solution = 400 ml
M1 being the molarity of the stock solution = 0.789 M
V2 being the volume of the diluted solution = 750 ml
M2 being the molarity of the diluted solution = ?
Now we have the molarity of the diluted solution by rearranging the above equation as,
M2 = [tex]$\frac{V1M1}{V2}[/tex]
Now plugin the values as,
M2 = [tex]$\frac{400 ml \times 0.789 M}{750 ml }[/tex]
= 0.421 M
So the molarity of diluted solution is found to be 0.421 M.
