Here are the missing information:
mass of empty crucible = 56.5622g
mass of crucible + hydrate before heating = 57.8310g
mass of crucible + hydrate after heating
(a) first reading = 57.6398g
(b) second reading = 57.6374g
(c) third reading = 57.6362g
Answers:
1)
57.8310g - 56.5622g = 1.2688 g hydrate
2)
57.6362g - 56.5622g = 1.07400 g anhydride
3)
57.8310g - 57.6362g = 0.1948 g water
4)
(0.1948 g water) / (1.2688 g hydrate) = 0.1535 = 15.35% water
5)
15.35% water = 84.65% BaCl2
(208.2330 g/mol BaCl2) / (0.8465) = 245.99 g/mol hydrate
((245.99 g/mol) - (208.2330 g/mol BaCl2)) / (18.01532 g H2O/mol) = 2.096
Round to the nearest whole number (2) to find the molar ratio of water to BaCl2:
BaCl2·2H2O
