Question

Il initially have à gas at a pressure of 12 atm, a volume of 23 liters, and a
temperature of 200 K, and then I raise the pressure to 14 atm and
increase the temperature to 300 K, what is the new volume of the gas?

Answer 1

The new volume of the gas is 29.6 L.

Explanation:

Using the ideal gas equation, we can find the new volume of the gas y cancelling the gas constant and number of moles as both are same in both the cases.

By using the equation,

$\frac{P1V1}{T1} = \frac{P2V2}{T2}$

P1, V1 and T1 are the initial values of Pressure, Volume and temperature of the gas and P2,V2 and T2 are the final values of Pressure, Volume and temperature of the gas.

We have to find the new volume by rearranging the equation as,

$V2=\frac{P1V1T2}{T1P2}$

$V2=\frac{12 atm \times 23 L \times 300 K}{200 K \times 14 atm}$

     = 29.6 L

So the new volume of the gas is 29.6 L.