The pressure and temperature inside a bike tire is 10 atm and 10 K
respectively, then the pressure of the tire when the temperature is increased 20 K is 20 atm.
Gay Lussac's Law states that at constant volume, temperature of the gas is deirectly proportional to the pressure of the gas and it is represented as:
P₁/T₁ = P₂/T₂, where
P₁ = initial pressure of tire = 10 atm
T₁ = initial temperature of tire = 10 K
P₂ = final pressure of tire = ?
T₂ = final temperature of tire = 20 K
On putting values we get,
P₂ = (10)(20) / (10) = 20 atm
Hence require pressure of the tire is 20 atm.
To know more about Gay Lussac's Law, visit the below link:
https://brainly.com/question/14812577
