Answer:
The answer to your question is 4699 g
Explanation:
Data
mass of Li₂CO₃ = ?
concentration = 12.7 M
volume = 5 l
Process
To solve this problem use the formula of Molarity and solve it for moles.
1.- Write the formula of Molarity
Molarity = moles / volume
-Solve it for moles
moles = Molarity x volume
2.- Substitute the values
moles = 12.7 x 5
3.- Result
moles = 63.5
4.- Calculate the molar mass of Li₂CO₃
Li₂CO₃ = (7 x 2) + (12 x 1) + (16 x 3)
= 14 + 12 + 48
= 74 g
5.- Use proportions to calculate the moles
74 g of Li₂CO₃ -------------- 1 mol
x -------------- 63.5 moles
x = (63.5 x 74 ) /
x = 4699 g
