Answer:
a. 3.64 m/s b. 7 revolutions
Explanation:
a. Linear acceleration
The linear acceleration,a = rα where r = radius of tyre = 0.260 m and α = angular acceleration = 14.0 rad/s².
a = rα = 0.260 m × 14.0 rad/s² = 3.64 m/s
b. Number of revolutions in 2.50 s
Using θ = ωt + 1/2αt² where θ = angular distance,ω = initial angular speed = 0(since it starts from rest) and t = 2.50 s
θ = 0 × 2.50s + 1/2(14.0 rad/s²)(2.50)² = 0 + 43.75 rad = 43.75 rad. So the number of revolutions is 43.75rad/2π = 6.96 revolutions ≅ 7.0 revolutions (since 1 revolution = 2π)
