Question

n horses, the hair color gene has a dominant allele B (Black) and a recessive allele b (Chestnut). The gait gene has a dominant allele T (Trotter), and a recessive allele t (Pacer). If a Black Trotter is heterozygous for both traits, how many types of allele combinations for these 2 traits can be found in the gametes it produces

Answer 1

Answer:

The answer is 9.

Explanation:

There are dominant and recessive genes for both the hair color gene and the gait gene in horses, B, b, T and t respectively.

If a black trotter is heterozygous that means it's genotype is going to be Bb and Tt, therefore it will possess both dominant and recessive genes for the two traits.

The allele combinations in the gametes it produces can be BBTT, BBTt, BBtt, BbTT, BbTt, Bbtt, bbTT, bbTt and bbtt .

I hope this answer helps.

Answer 2

Answer:

Four (4). BT, Bt, bT and bt

Explanation:

The hair color has two alleles, dominant B for black and recessive b for chestnut.

The gait also has two alleles, dominant T for trotter and recessive t for pacer.

Heterozygous black trotter will have the genotype BbTt.

Gametes usually have half the amount of allele of the parents

BbTt can have the the following allelic combination in its gamete: BT, Bt, bT and bt.

Hence, there are four (4) possible types of allele combinations for the two traits and they are BT, Bt, bT and bt.

You can see the attached image for the Punnet square analysis of the gametic alleles.