1031.9 K is the the kelvin temperature required for 0.0140 mol of gas to fill a balloon to 1.20L under 0.988 atm a pressure.
Explanation:
Data given:
number of moles of the gas = 0.0140
volume of the balloon= 1.20 litres
pressure of the gas = 0.988 atm
Kelvin temperature =?
R = 0.08206 L.atm/mole K
Formula used of ideal gas Law:
PV = nRT
putting the values in the equation after rearranging it:
T = [tex]\frac{PV}{nR}[/tex]
=[tex]\frac{ 1.20 X 0.988}{0.0140 X 0.08206}[/tex]
T = 1031.9 K
In the equation when the pressure is in atm, volume in litres, Gas constant has a value of 0.08206 L.atm/mole K and number of moles as moles the temperature unit is in Kelvin.
